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if(use_sse2) {
int b = (int)(src_stride / sizeof(int16_t));
int w = max_w/b;
while (w–) {
int j = max_h-i;
__m128i sum = _mm_set_epi32(0,0,0,0);
for (int k=0; k0)
sum = _mm_slli_epi32(sum, 2);
sum = _mm_packs_epi32(sum, sum);
int d = _mm_cvtsi128_si32(sum);
tmp[i*b] = (float)(d);
tmp[i*b+1] = (float)(-d);

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You can do it in many ways:

// (setq xxx (list 1 2 3 4 5 6))
.

A:

The best way to do this is via an interactive REPL with read-string, and maybe eval-last-sexp. The user will be able to type whatever commands they want (in whatever order) and the result will be printed to the REPL. You could also open and close file instances, eval things, read with read-char, etc.
What you did in your code is perfectly fine, but is extremely limited.
It’s important to note that the result of the above (returning the list 1 2 3 4 5 6) is now a reader and not a list, so there’s no easy way to append the results of your step to the prior.

;;; Generating a list of all the required commands…
(defun repeat-string-x (string &optional n)
“Repeat STRING N times.
If N is given as a negative number, it is assumed to be a positive number
that would be subtracted from the length of STRING. The effect is to repeat
STRING a number of times larger than the actual length of STRING. This
function provides an idiomatic Common Lisp solution to the problem of
repeating some data.”
(while (not (equal string “”))
(if n
(progn
(setq string (substring string 0 n))
(setq n (- n 1)))
(setq string (substring string 0 n)))
string))

(defmacro repeat-string-x (string &optional n)
“Repeat STRING N times.
If N is given as a negative number, it is assumed to be a positive number
that would be subtracted from the length of STRING. The effect is to repeat
STRING a number of times larger than the actual length of STRING. This
function provides an idiomatic Common Lisp solution to the problem of
repeating some data.”
`(if (not,(< (symbol-name string) 0),n) (progn (setq string (substring string 0,(